Question

the difference between the ages of two cousins is 10 years 15 years ago if the elder one was twice as old as the younger one find the present ages​

Answer 1

Solution. Cousin 1 – x. Cousin 2 – y. The difference between the ages of two cousins is 10 years: ? − ? =10 15 years ago, if the elder one was twice as old as the younger one: ? −15=2( ? −15) So, we obtain the system of two equations: { ? − ? =10 ? −15=2( ? −15) → 10+ ? −15=2( ? −15) → ? =25→ ? =35 Answer. Cousins present ages are 25 and 35 years.

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Answer 2

15 yrs ago let the age of younger cousin be "x".

and the age of older cousin be "2x".

Now after 15 yrs the age of younger cousin is " x + 15 "

and the age of older cousin is " 2x + 15 "

The difference between the two cousins is 10.

that is ,

(2x + 15) - (x + 15) = 10

=> 2x + 15 - x - 15 = 10

=> 2x - x + 15 - 15 = 10

=> x = 10

If 15 yrs ago the age of younger cousin is 10 .

Then the present age of younger cousin is x+15

= 10 + 15 = 25 years

And the present age of older cousin is 2x + 15

= (2 × 10) + 15

= 20 + 15

= 35 years