the difference between the ages of two cousins is 10 years .15 years ago the elder one was twice as old as the younger one find their present ages
Answers
Answered by
16
Let the age of younger one be x yrs.
Then then the age of younger one 15 yrs ago =(x-15) yrs.
Elder's age =2(x-15) yrs.
According to the Question
2(x-15)-(x-15)=10
2x-30-x+15=10
x-15=10
x=25
Therefore the age of younger one is 25 yrs
Age of elder one 15 yrs ago =2(25-15)
= 2*10
=20yrs
Therefore present age of elder one is 20+15=35yrs
Then then the age of younger one 15 yrs ago =(x-15) yrs.
Elder's age =2(x-15) yrs.
According to the Question
2(x-15)-(x-15)=10
2x-30-x+15=10
x-15=10
x=25
Therefore the age of younger one is 25 yrs
Age of elder one 15 yrs ago =2(25-15)
= 2*10
=20yrs
Therefore present age of elder one is 20+15=35yrs
Similar questions