Math, asked by ashishnarigara6319, 11 months ago

The difference between the ages of two cousins is 10 years 15 years ago the elder one was twice as old as a younger one find their present ages

Answers

Answered by sdjoshi2502
9
cousin 1 = x(elder)
cousin 2=y(younger)
x - 15 = 2(y - 15)
x - y = 10 \\ x = 10 + y
THEREFORE,
10 + y - 15 = 2y - 30 \\ y - 5 = 2y - 30 \\ 2y - y = 30 - 5 \\ y = 25
THEREFORE,
x = 10 + 25 \\  x  = 35
ANSWER:
x = 35 \\ y = 25
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