The difference between the ages of two cousins is 10 years 15 years ago the elder one was twice as old as a younger one find their present ages
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cousin 1 = x(elder)
cousin 2=y(younger)
![x - 15 = 2(y - 15) x - 15 = 2(y - 15)](https://tex.z-dn.net/?f=x+-+15+%3D+2%28y+-+15%29)
![x - y = 10 \\ x = 10 + y x - y = 10 \\ x = 10 + y](https://tex.z-dn.net/?f=x+-+y+%3D+10+%5C%5C+x+%3D+10+%2B+y)
THEREFORE,
![10 + y - 15 = 2y - 30 \\ y - 5 = 2y - 30 \\ 2y - y = 30 - 5 \\ y = 25 10 + y - 15 = 2y - 30 \\ y - 5 = 2y - 30 \\ 2y - y = 30 - 5 \\ y = 25](https://tex.z-dn.net/?f=10+%2B+y+-+15+%3D+2y+-+30+%5C%5C+y+-+5+%3D+2y+-+30+%5C%5C+2y+-+y+%3D+30+-+5+%5C%5C+y+%3D+25+)
THEREFORE,
![x = 10 + 25 \\ x = 35 x = 10 + 25 \\ x = 35](https://tex.z-dn.net/?f=x+%3D+10+%2B+25+%5C%5C++x++%3D+35)
ANSWER:
![x = 35 \\ y = 25 x = 35 \\ y = 25](https://tex.z-dn.net/?f=x+%3D+35+%5C%5C+y+%3D+25)
HOPE THIS HELPS!!!
ALL THE BEST
DO MARK AS THE BRAINLIEST!!!!!
cousin 2=y(younger)
THEREFORE,
THEREFORE,
ANSWER:
HOPE THIS HELPS!!!
ALL THE BEST
DO MARK AS THE BRAINLIEST!!!!!
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