The difference between the ages of two cousins is ten years. Fifteen years ago, if the elder one was twice as old as the younger one, find their present ages.
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Answer:
Cousin 1 – x.
Cousin 2 – y.
The difference between the ages of two cousins is 10 years:
− = 10
15 years ago, if the elder one was twice as old as the younger one:
− 15 = 2( − 15)
So, we obtain the system of two equations:
{
− = 10
− 15 = 2( − 15)
→
10 + − 15 = 2( − 15) → = 25 →
= 35
Cousins present ages are 25 and 35 years.
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