Math, asked by kulkarnianjalisharad, 11 months ago

the difference between the ages of two sisters is 3 years . six years hence the ratio of their ages will be 7 : 6 . what is the age of each sister today ?​

Answers

Answered by Anonymous
20

Answer:

\large\bold\red{12\:yrs\:and\:15\:yrs}

Step-by-step explanation:

Let's assume that,

  • First Sister = S1
  • Second Sister = S2

Now,

Let's take ,

The present age of S1 = x yrs.

Therefore,

The present age of S2 = (x+3) yrs.

After 6 yrs,

Age of S1 = (x+6) yrs.

And,

Age of S2 = (x+9) yrs.

Now,

According to question,

We get,

 =  >   \frac{x + 9}{x + 6}  =  \frac{7}{6}  \\  \\  =  > 6(x + 9) = 7(x + 6) \\  \\  =  > 6x + 54 = 7x + 42 \\  \\  =  > 7x - 6x = 54 - 42 \\  \\  =  > x = 12

Therefore,

 =  > x + 3 = 15

Hence,

Present age of S1 = 12 yrs.

And,

Present age of S2 = 15 yrs.

Answered by EliteSoul
1

Answer:

Age of one sister: 15 years.

Age of another sister:12 years.

\huge\underline\mathfrak\blue{Solution..}

Let the age of one sister be "X" years

Let the age of another sister be "Y" years.

First equation is:

X-Y =3

So, X =Y +3..............(i)

Second equation is:

(x+6):(y+6)=7:6

or, (X+6)/(Y+6)=7/6

or, 6(X+6)=7(Y+6)

or, 6X+36=7Y+42

or, 6X =7Y+42-36

or, 6X =7Y+6

So, X =(7Y+6)/6.............(ii)

Then by substituting the value of (i) equation we get,

Y+3=(7Y+6)/6

or, (7Y+6)/6=Y+3

or, 7Y+6=6(Y+3)

or, 7Y+6=6Y+18

or, 7Y-6Y=18-6

So, Y =12⭐⭐⭐

So, Second sister's present

age is: 12 years.

By substituting the value of Y into the (i) equation we get,

X =12+3

So, X =15⭐⭐⭐

So,First sister's age is :15

years.

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