the difference between the ages of two sisters is 3 years . six years hence the ratio of their ages will be 7 : 6 . what is the age of each sister today ?
Answers
Answered by
20
Answer:
Step-by-step explanation:
Let's assume that,
- First Sister = S1
- Second Sister = S2
Now,
Let's take ,
The present age of S1 = x yrs.
Therefore,
The present age of S2 = (x+3) yrs.
After 6 yrs,
Age of S1 = (x+6) yrs.
And,
Age of S2 = (x+9) yrs.
Now,
According to question,
We get,
Therefore,
Hence,
Present age of S1 = 12 yrs.
And,
Present age of S2 = 15 yrs.
Answered by
1
Answer:
Age of one sister: 15 years.
Age of another sister:12 years.
Let the age of one sister be "X" years
Let the age of another sister be "Y" years.
First equation is:
X-Y =3
So, X =Y +3..............(i)
Second equation is:
(x+6):(y+6)=7:6
or, (X+6)/(Y+6)=7/6
or, 6(X+6)=7(Y+6)
or, 6X+36=7Y+42
or, 6X =7Y+42-36
or, 6X =7Y+6
So, X =(7Y+6)/6.............(ii)
Then by substituting the value of (i) equation we get,
Y+3=(7Y+6)/6
or, (7Y+6)/6=Y+3
or, 7Y+6=6(Y+3)
or, 7Y+6=6Y+18
or, 7Y-6Y=18-6
So, Y =12⭐⭐⭐
So, Second sister's present
age is: 12 years.
By substituting the value of Y into the (i) equation we get,
X =12+3
So, X =15⭐⭐⭐
So,First sister's age is :15
years.
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