Question

The difference between the area of the outer and the inner square of a circle is 63 centimeter square and O is the center of the circle. Find the area of the circle.

Answer 1

Answer:77 CM square

Step-by-step explanation:

Answer 2

The area of circle=99 square centimeter

Step-by-step explanation:

Let r be the radius of circle

We know that diagonals of square perpendicularly bisect to each other.

Side of inner square=$\sqrt{r^2+r^2}=r\sqrt 2$

By using Pythagoras theorem

Diameter of circle=2r

Side of outer square =Diameter of outer circle

Side of outer square =2r

Area of inner square =$r\sqrt 2\times r\sqrt 2=2r^2$

By using the formula area of square=$side \times side$

Area of outer square =$2r\times 2r=4r^2$

According to question

Area of outer square -area of inner square =63 square cm

$4r^2-2r^2=63$

$2r^2=63$

$r^2=\frac{63}{2}$

$r=\sqrt{\frac{63}{2}$

Area of circle=$\pi r^2$

Area of circle=$\frac{22}{7}\times \frac{63}{2}=99cm^2$

Hence, the area of circle=99 square centimeter

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https://brainly.in/question/14170681:Answered by Eudora