Question

The difference between the areas of a
rectangle and square is 35 cm². If the rectangle's
length and breadth are 50% more and 10% less
respectively than the side of the square, what is the
area of the rectangle? (in cm?)​

Answer 1

Answer:

Thus ar(Rectangle)=ar(square)+35

=100+35

=135 cm²

Step-by-step explanation:

let the side of sqr is x the area=x²

length of  rectanglr is 50% more than x

so length l=(150x/100)=1.5x

breadth=10% less of x

=(90x/100)=0.9x

Thus are of rectangle=1.5x*0.9x=1.35x cm²

as per given

ar(rectangle)-ar(square)=35

1.35x²-x²=35

0.35x²=35

x²=35/0.35=100

so ar(square)=x²=100 cm²

thus ar(Rectangle)=ar(square)+35

=100+35

=135 cm²

Answer 2

Answer:

Step-by-step explanation: