Math, asked by flower12, 1 year ago

the difference between the C.I and S.I on a certain sum o money at 10 % p.a. for 2 years is Rs.500 . Find the sum when the interest is compounded yearly .

Answers

Answered by YaminiRathi
3
SI = p*10*2/100
= 20p/100
CI = p{(1+10/100)² - 1()
= p{(11/10)² - 1}
=p{(11)²-(10)²/(10)²}
= p(121-100/100)
= 21p/100
Now,
CI - SI = 500
21p/100 - 20p/100 = 500
or 21p - 20p/100 =500
or p = 50000
Answered by NikhilBisht0
2
Let principal=p

R=10%

T=2years

S.I.=P×R×T/100

=p×10×2/100

=p×1/5

= 1/5p

C.I.=P[(1+R/100)^2-1]

=p[(1+10/100)^2-1]

=p[(11/10)^2-1]

=p[121-100/100]

=21/100p

Difference=Rs500

C.I.-S.I. =Rs500

21/100p-1/5p=500

21p-20p/100=500

1/100p=500

p=500×100

p=Rs50000

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