the difference between the C.I and S.I on a certain sum o money at 10 % p.a. for 2 years is Rs.500 . Find the sum when the interest is compounded yearly .
Answers
Answered by
3
SI = p*10*2/100
= 20p/100
CI = p{(1+10/100)² - 1()
= p{(11/10)² - 1}
=p{(11)²-(10)²/(10)²}
= p(121-100/100)
= 21p/100
Now,
CI - SI = 500
21p/100 - 20p/100 = 500
or 21p - 20p/100 =500
or p = 50000
= 20p/100
CI = p{(1+10/100)² - 1()
= p{(11/10)² - 1}
=p{(11)²-(10)²/(10)²}
= p(121-100/100)
= 21p/100
Now,
CI - SI = 500
21p/100 - 20p/100 = 500
or 21p - 20p/100 =500
or p = 50000
Answered by
2
Let principal=p
R=10%
T=2years
S.I.=P×R×T/100
=p×10×2/100
=p×1/5
= 1/5p
C.I.=P[(1+R/100)^2-1]
=p[(1+10/100)^2-1]
=p[(11/10)^2-1]
=p[121-100/100]
=21/100p
Difference=Rs500
C.I.-S.I. =Rs500
21/100p-1/5p=500
21p-20p/100=500
1/100p=500
p=500×100
p=Rs50000
R=10%
T=2years
S.I.=P×R×T/100
=p×10×2/100
=p×1/5
= 1/5p
C.I.=P[(1+R/100)^2-1]
=p[(1+10/100)^2-1]
=p[(11/10)^2-1]
=p[121-100/100]
=21/100p
Difference=Rs500
C.I.-S.I. =Rs500
21/100p-1/5p=500
21p-20p/100=500
1/100p=500
p=500×100
p=Rs50000
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