Math, asked by eelizajaved9482, 11 months ago

The difference between the compound interest and simple interest for 2 years on a sum of money is rs. 60. If the simple interest for 2 years be rs. 1440, the rate percent is:-

Answers

Answered by sonuvuce
4

Answer:

The rate of interest is 8.33%

Step-by-step explanation:

Let the rate of interet is r% and amount be Rs. P

If the principle amount is P, rate r% and number of years n then the simple interest is given by

\boxed{I=\frac{Prn}{100}}

And the interest after two years if compound interest is applicable, is given by

\boxed{I=P-P(1+\frac{r}{100})^n}

Thus

Simple interest after 2 years = 1440

\implies \frac{P\times r\times2}{100}=1440

\implies P\times r=1440\times 100/2

\implies P\times r=72000

The comound interest will be

I=P-P(1+\frac{r}{100})^2

According to the question

P-P(1+\frac{r}{100})^2-1440=60

\implies P[1-(1+\frac{r}{100})^2]=60+1440

\implies \frac{72000}{r} [1-1+\frac{2r}{100}+\frac{r^2}{10^4} ]=1500

\implies \frac{72000}{r} [\frac{200r+r^2}{10000}]=1500

\implies \frac{72r}{r} [\frac{200+r}{10}]=1500

\implies 200+r=1500\times\frac{10}{72}

\implies 200+r=208.33

\implies r=208.33-200=8.33

Therefore, the rate of interest is 8.33%

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