The difference between the compound interest and simple interest on a certain sum for 3 years at 5% p.a. is rs.183. Find the sum.
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Given,
Time = 3 years
Rate = 5% p. a.
Let the sum be ₹ P.

CI = { p × ( 1 + r / 100 )^t – p }
= { p × ( 1 + 5 / 100 )^3 – p }
= { p × ( 1 / 20 )^3 – p }
= ( p × 21/20 × 21/20 × 21/20 – p)

According to question,
CI – SI = 183

Hence, the sum is ₹ 24000
Hope it help you
Given,
Time = 3 years
Rate = 5% p. a.
Let the sum be ₹ P.
CI = { p × ( 1 + r / 100 )^t – p }
= { p × ( 1 + 5 / 100 )^3 – p }
= { p × ( 1 / 20 )^3 – p }
= ( p × 21/20 × 21/20 × 21/20 – p)
According to question,
CI – SI = 183
Hence, the sum is ₹ 24000
Hope it help you
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