Question

the difference between the compound interest and the simple interest on a certain sum of money at 15% per annum for 3 years is rupees 283. 50 find the sum​

Answer 1

Answer:

Step-by-step explanation:

Given

CI-SI =rs 283.50

Rate of interest is 15%

N=3 years time

We know that

P(1+r/100) n

=y(1+5/100) 3

Y(1.15) ____1

Si=PTR/100

=y(15) (3) /100

=0.45y____2

This we have(1.15) 3-1.45y=283.50 from 1 and 2

1.523y-1.45y=283.50

Y=283.50/0.070875

= 4000

The sum is RS 4000

Answer 2

Step-by-step explanation:

C.I= p[(1 + 15/100)^3 - 1]

C.i =0.520875p

s.i = p×15×3/100 = 0.45p

C.I - S.I = 283.50

0.520875p - 0.45p= 283.50

0.070875p = 283.50

p = Rs 4000

required sum = Rs4000 Answer