Question

the difference between the compound interest and the simple interest on a sum of money for 1.5 years at 12% per annum is rupees 150 calculate the amount​

Answer 1

Answer:

Rs. 28320.12

Step-by-step explanation:

The amount after applying a simple interest is given as

$A_1=P*(1+\frac{i}{100}*t)\\ A_1=P*(1+\frac{12}{100}*1.5)\\ A_1=P*1.18\\</p><p></p><p>The amount after applying compound interest is given by the formula</p><p>[tex]A_2=P*(1+\frac{i}{100})^t\\ A_2=P*(1+\frac{12}{100})^{1.5}\\ A_2=P*1.185296587\\A_2=1.185296587P$

If the difference between these two amounts is 150, then

$A_2-A_1=150\\1.185296587P-1.18P=150\\0.005296587357P=150\\P=28320.12198$

Answer 2

Answer: 20833.33

Explanation:

Given:

Amount at the end of the year: 112

Amount at the end of the 1.5 year: 112 * 1.06

To find: Amount

As we have Simple interest of at the end of 1.5 years = 118

Difference in compound interest and simple interest = 118.72–118 = 0.72

The difference in Principal amount is = rupees 150

Therefore,

Amount = 100*150/0.72 = 20833.33

Hence, The total amount is 20833.33

Method II :

Given:

Compound Interest for 1.5 year = 18.72%

Simple Interest FOR 1.5 YEARS = 18%

We get % of 150..

Therefore,

0.72 % = 150

To find => 100%= ?

Amount= 100×150/0.72 = 20833.33