the difference between the compound Interest and the simple Interest on a certain for 3 years at 10% per annum is Rs 93.find the sum.
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Heya friend,
______________________________
Let ₹P be the principal. Then,
S.I. = P×R×T/100
= P×10×3/100
= ₹3 P/10
C.I. = P{(1+R/100)^n - 1}
= P{(1+10/100)^3 - 1}
= P{(100+10/100)^3 - 1}
= P{(110/100)^3 - 1}
= P{(11/10)^3 - 1}
= P{1,331/1,000 - 1}
= P{1,331 - 1,000/1,000}
= ₹331 P/1,000
Difference = 331 P/1,000 - 3 P/10
=> 93 = 331 P - 300 P/1,000
=> 93 = 31 P/1,000
=> P = 93×1,000/31
=> P = ₹3,000
Hence, the sum is ₹3,000.
Thanks
With regards@
Tanisha
______________________________
Let ₹P be the principal. Then,
S.I. = P×R×T/100
= P×10×3/100
= ₹3 P/10
C.I. = P{(1+R/100)^n - 1}
= P{(1+10/100)^3 - 1}
= P{(100+10/100)^3 - 1}
= P{(110/100)^3 - 1}
= P{(11/10)^3 - 1}
= P{1,331/1,000 - 1}
= P{1,331 - 1,000/1,000}
= ₹331 P/1,000
Difference = 331 P/1,000 - 3 P/10
=> 93 = 331 P - 300 P/1,000
=> 93 = 31 P/1,000
=> P = 93×1,000/31
=> P = ₹3,000
Hence, the sum is ₹3,000.
Thanks
With regards@
Tanisha
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