Question

the difference between the compound interest and the simple interest on a certain sum at 11% per annum for 2 year is 36 find the sum​

Answer 1

Answer:

Assume the sum amount it may be x if want to make equation or Rs 100 if want to solve on propirtionate basis. I solve it by assuming it at Rs.100.

Simple interest for 2 years at 11%PA

I=PXRXT÷100

I=100X11X2÷100

INTEREST= 22

Comoound interest for 2 years at 11%PA

A =P(1+R/100)^T

A=100(1+11/100)^T

A=123.21

Interest=123.21–100=23.21

Difference interest on compound &simple interest on Rs. 100 is

= 23.21–22=1.21

Then diference of Rs. 36 will be on amount of =100÷1.21x36

=Rs. 2975.20

You may verify the answer.

Step-by-step explanation:

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Answer 2

Answer:    $Rs. 2975.20$

Step-by-step explanation:

2 year simple interest rate at 11% PA

$I = P*R*T / 100$

$I = 100X11X2 ÷ 100$

INTEREST $= 22$

2 year compound interest  at $11$% PA

$A = P (1 + R / 100 ) ^ T$

$A = 100 (1 + 11/100) ^ T$

$A = 123.21$

Interest $= 123.21–100 = 23.21$

The difference between compound and simple interest per $Rs. 100$ is

$= 23.21–22 = 1.21$

Then the difference of Rs. 36 will be worth = $100$ $/ 1.21 * 36$

$= Rs. 2975.20$

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