The difference between the compound interest and the simple interest on a certain sum for 2 years at 5% per annum is Rs.400.Find the sum.
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let the sum be 100rs. then
si= p×r×t/100
=100×5%×2÷100
= 10
and c.I={p(1+r%/100)²-p}
={100(105)²-100}
=xyz
c.i -s.I
xyz - s.I= ABC.
if(c.I -s.I) is rs400 then the sum is (100× difference between c.I -s.I which is mentioned as xyz.×400
si= p×r×t/100
=100×5%×2÷100
= 10
and c.I={p(1+r%/100)²-p}
={100(105)²-100}
=xyz
c.i -s.I
xyz - s.I= ABC.
if(c.I -s.I) is rs400 then the sum is (100× difference between c.I -s.I which is mentioned as xyz.×400
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