Question

The difference between the compound interest and the simple interest on a certain principal at the rate of 15% per annum for 3 years is ₹283.50 . Find the sum .​

Answer 1

Answer:

this is answer

Step-by-step explanation:

let the sum be P

SI = PTR/100=P*3*15/100=45P/100=9P/20

CI = A-P=P (1+R/100)^n-P=P (1+15/100)^3-P

=P (115/100)^3-P

=P (23/20)^3-P

So by question CI-SI = 283.50

or P ((23/20)^3-1)-9P/20=P ((23/20)^3-1-9/20)=283.50

or P= 283.50/((23/20)^3-29/20)

or P = 4000 (ans)

Answer 2

★$\large {\bold {\bf {\blue {\underbrace {QUESTION }}}}}$★

The difference between the compound interest and the simple interest on a certain principal at the rate of 15% per annum for 3 years is ₹283.50 . Find the sum .

★$\large {\bold {\bf {\blue {\underbrace {ANSWER }}}}}$★

Given ,

CI - SI = ₹283.50

R = 15%

n = 3 years

Let the sum be Rs.x

We know that :

$\large {\blue {\boxed {\bf {\pink {A = P (1 + \frac {R}{100})ⁿ}}}}}$

→${A = 2 (1 + \frac {5}{100})³ = x (1.15)³--- (1)}$

Also,

$SI = \frac {PRT}{100} = \frac {x × 15 × 3}{100} = 1.45x --- (2)$

Thus, we have :

x (1.15)³ - 1.45x = 283.50 (from (1)&(2))

⇒1.523x − 1.45x = 283.50

⇒0.070875x = 283.50

⇒x = $\frac{283}{0.070875} = 4,000$

Thus, the sum is 4,000.

hope it helps dear...☺️✌