Question

the difference between the cube and the square of a natural number is 30 times the number, what is the square root of that number?

Answer 1

Let us assume the natural number as x

Now

According to question,

x^3-x^2=30x

x(x^2-x)=30x

Cancelling x on both sides

x^2-x-30=0

By solving,

X=6,-5

$\sqrt{x} = \sqrt{6 \: }$

$\sqrt{x } = \sqrt{ - 5}$