The difference between the digit of two digit number is 4 and the sum of the number and the no formed by reversing its digit is 110 find the no
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Let the tens place digit be x and units place digit be y
so the number is 10x + y
and the number obtained by reversing the digits is 10y + x
by the condition given in your question we get equations
x - y = 4
10x + y + 10y + x = 110
11x + 11y = 110
x + y = 10
by adding the equations ( l ) & ( ll ) we get
2x = 14
x = 7
putting x = 7 in equation ( ll ) we get
7 + y = 10
y = 3
so the number is 73
so the number is 10x + y
and the number obtained by reversing the digits is 10y + x
by the condition given in your question we get equations
x - y = 4
10x + y + 10y + x = 110
11x + 11y = 110
x + y = 10
by adding the equations ( l ) & ( ll ) we get
2x = 14
x = 7
putting x = 7 in equation ( ll ) we get
7 + y = 10
y = 3
so the number is 73
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