Question

the difference between the digits of a two-digit number is 2. if the digit in the ten's place and the digit in the unit's place are in the ratio 3:2, find the number.​

Answer 1

Answer:

64

Step-by-step explanation:

let the digits of number be x and y where x in ten's place and y in units place

Given:

• x-y = 2 ---(1)
• x/y = 3/2

To find:

• 10x+y

Solution:

x/y = 3/2

y+2/y = 3/2 (from (1) x=y+2)

2y+4 = 3y. (cross multiplication)

3y-2y = 4

y = 4

x-4 = 2

x = 6

so the number is 10x+y = 10×6+4 = 64

Verification:

x-y = 2

6-4 = 2 ---> verified

x/y = 3/2

6/4 = 3/2 ----> verified