Question

The difference between the digits of a two digit number is 3. If the digits of the number are reversed and added to the original number, the sum is 143. Fond the original number.

Answer 1

let the digits of the no. be xy such that the no. is 10x+y

x-y=3

reverse no.=10y+x

11x+11y=143

x+y=13

y=5

x=8, so the no. can be 58 or 85

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Answer 2

Let us assume, the x is the tenth place digit and y is the unit place digit of the two-digit number. Also assume x > y

Therefore, the two-digit number is 10x + y and reversed number is 10y + x

Given:

x - y = 3 ---------------1

Also given:

10x + y + 10y + x = 143

11x + 11y = 143

x + y = 13 ---------------2

Adding equation 1 and equation 2

2x = 16

x = 8

Therefore, y = x - 3 = 8 - 3 = 5

Therefore, the two-digit number = 10x + y = 10 * 8 + 5 = 85