Math, asked by hanumannonpura, 5 months ago

The difference between the exterior angle of a ( n - 1 ) sides regular polygon and a ( n - 1 ) sides regular polygon is 15 . find the value of n​

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Answered by poojarnadar
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Step-by-step explanation:

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answrLOGINJOIN NOWWhat would you like to ask−1)360o

answrLOGINJOIN NOWWhat would you like to ask−1)360oAn exterior angle of (n+2) sided regular polygon = (n+2)360o

answrLOGINJOIN NOWWhat would you like to ask−1)360oAn exterior angle of (n+2) sided regular polygon = (n+2)360oTheir difference is 6o

answrLOGINJOIN NOWWhat would you like to ask−1)360oAn exterior angle of (n+2) sided regular polygon = (n+2)360oTheir difference is 6oSo,

answrLOGINJOIN NOWWhat would you like to ask−1)360oAn exterior angle of (n+2) sided regular polygon = (n+2)360oTheir difference is 6oSo,(n−1)360o−(n+2)360o=6o

answrLOGINJOIN NOWWhat would you like to ask−1)360oAn exterior angle of (n+2) sided regular polygon = (n+2)360oTheir difference is 6oSo,(n−1)360o−(n+2)360o=6o=>60(n−1)(n+2)(n+2)−(n−1)=1

answrLOGINJOIN NOWWhat would you like to ask−1)360oAn exterior angle of (n+2) sided regular polygon = (n+2)360oTheir difference is 6oSo,(n−1)360o−(n+2)360o=6o=>60(n−1)(n+2)(n+2)−(n−1)=1=>(n−1)(n+2)=180

answrLOGINJOIN NOWWhat would you like to ask−1)360oAn exterior angle of (n+2) sided regular polygon = (n+2)360oTheir difference is 6oSo,(n−1)360o−(n+2)360o=6o=>60(n−1)(n+2)(n+2)−(n−1)=1=>(n−1)(n+2)=180=>n2+n−2=180

answrLOGINJOIN NOWWhat would you like to ask−1)360oAn exterior angle of (n+2) sided regular polygon = (n+2)360oTheir difference is 6oSo,(n−1)360o−(n+2)360o=6o=>60(n−1)(n+2)(n+2)−(n−1)=1=>(n−1)(n+2)=180=>n2+n−2=180=>n2+

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