the difference between the inner and outer surface of a cylendrical pipe is 88sq cm.if the height of the cylendrical pipe is 14cm and volume is 176 cube cm,find the inner and the outer radii
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H = 14 cm
2 π R H - 2 π r H = 88 cm²
2 π H (R - r) = 88
R - r = 88 / (2 π * 14) = 1 cm
It is not clear if the volume of the material is given OR, the external volume of the pipe is given.
case 1)
Volume of the material in the pipe is = 176 cm³
π R² H - π r² H = 176
R² - r² = 176 /(π * 14) = 4
(R+r)(R-r) = 4
R+r = 4 cm as R-r = 1 cm
solving these two equations, we get R = 2.5 cm and r = 1.5 cm
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case 2)
external volume of the pipe = 176 cm³
π R² H = 176 cm³
R² = 176 / (π*14) = 4
R = 2 cm
r = 1 cm
2 π R H - 2 π r H = 88 cm²
2 π H (R - r) = 88
R - r = 88 / (2 π * 14) = 1 cm
It is not clear if the volume of the material is given OR, the external volume of the pipe is given.
case 1)
Volume of the material in the pipe is = 176 cm³
π R² H - π r² H = 176
R² - r² = 176 /(π * 14) = 4
(R+r)(R-r) = 4
R+r = 4 cm as R-r = 1 cm
solving these two equations, we get R = 2.5 cm and r = 1.5 cm
=======================
case 2)
external volume of the pipe = 176 cm³
π R² H = 176 cm³
R² = 176 / (π*14) = 4
R = 2 cm
r = 1 cm
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