Question

The difference between the inner and Outer surfaces of a cylindrical pipe is 88 sq.cm if the height of the cylindrical pipe is 14cm and the volume is 176 cu.cm,find the inner and outer radii of the pipe.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Outer radius of the pipe = R=2.5 cm

Outer radius of the pipe = R=2.5 cminner radius = r = 1.5 cm

Step-by-step explanation:

Let Outer radius of the pipe = R cm

inner radius = r cm

Height of the pipe (h) = 14 cm

The difference between the inner and Outer surfaces of a cylindrical pipe is 88 sq.cm

$2\pi Rh - 2\pi rh = 88$

$\implies 2\pi h (R-r) = 88$

$\implies 2\times \frac{22}{7}\times 14 (R-r) = 88$

$\implies 88(R-r)=88$

$\implies R-r = 1\:---(1)$

Volume of the pipe = 176 c.cm

$\pi R^{2} h - \pi r^{2} h = 176$

$\implies \pi h( R^{2}-r^{2})=176$

$\implies \frac{22}{7}\times 14(R+r)(R-r)=176$

$\implies 44(R+r)\times 1 = 176$

$\implies R+r = \frac{176}{44}$

$\implies R+r = 4\:---(2)$

/* Add equations (1) and (2) , we get

$\implies 2R = 5$

$\implies R = \frac{5}{2}=2.5\:cm$

/* Substitute R = 2.5cm in equation (2), we get

[tex ] r = 4-2.5= 1.5 \:cm [/tex]

Therefore,.

Outer radius of the pipe = R=2.5 cm

inner radius = r = 1.5 cm

•••♪