Question

The difference between the length and breadth of a rectangle is 33 m. If its perimeter is 134 m, then its area is: ​

Answer 1

Answer:

850m².

Step-by-step explanation:

Steps:

Given,

Perimeter of the rectangle = 2[l + b] = 134m

==> 2[l + b] = 134

==> l + b = 134/2 = 67 -------(1)

The difference between the length and breadth of a rectangle = 33m

==> l - b = 33 ------------(2)

Solve eq - (1) & (2)

==> 2L = 100

==> l = 100/2

==> l = 50

Length = 50m

Substitute l = 50 in eq - (1)

==> (50) + b = 67

==> b = 67 - 50

==> b = 17

Breadth = 17m

We know that,

Area of Rectangle = length × breadth

==> = 50 × 17

==> = 850m²

Therefore, the area of Rectangle is 850m².

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Answer 2

Answer:

The area is 850 m².

Step-by-step explanation:

Solution:

Length and breadth differ by = 33 m

Perimeter = 134 m

Area = ??

Let the -

• Breadth be b
• Length be (b + 33)

★ Perimeter =

⇒ 2(Length + Breadth)

⇒ 2(b + 33 + b) = 134

⇒ 2b + 33 = 67

⇒ 2b = 34

⇒ b = 34/2

⇒ b = 17

Breadth = 17

★ Length =

⇒ 17 + 33

⇒ 50

Length = 50

★ Area =

⇒ Length × Breadth

⇒ 50 × 17

⇒ 850 m²

Therefore, the area is 850 m².