Question

The difference between the length and breadth of a rectangle is 8 cm dha
the perimeter is 64 find length and breadth​

Answer 1

Step-by-step explanation:

LET LENGTH =x

WIDTH=y

ACCORDING TO THE QUESTION,

$x - y = 8 \\ x = 8 + y \: . \: . \: ..(1)\\ \\ perimeter = 64 \\ 2(x + y) = 64 \\ 2(8 + y + y) = 64 \\ 2(8 + 2y) = 64 \\ 16 + 4y = 64 \\ 4y = 64 - 16 \\ 4y = 48 \\ y = \frac{48}{4} \\ y = 12 \\ put \: the \: value \: in \: eq(1) \\ x = 8 + 12 \: \\ x = 20$

LENGTH=x=20 cm

WIDTH=y=12 cm

Answer 2

Step-by-step explanation:

let the length and breadth be x,y respectively

difference between x&y is 8

:- x = y - 8

perimeter of rectangle = 2(l + b)

perimeter of rectangle = 64

:- 2(x + y) = 64

2[(y - 8) + y) = 64

(y + y - 8 ) = 64/2

2y - 8 = 32

2y = 32 - 8

2y = 24

y = 24/2

y = 12 cm. x=length =y - 8=(12) - 8=4cm

y= breadth = 12 cm