Question

The difference between the length and breadth of a rectangle is 25 meters. If the perimeter of this rectangle is 210 meters, what is its area?​

Answer 1

Answer:

2600 m sq

Step-by-step explanation:

we should equate the given equations and solve the problem

Answer 2

The area of the given rectangle is 2600 m².

The difference between the length and breadth of a rectangle is 25 meters. If the perimeter of this rectangle is 210 meters.

We have to find the area of rectangle.

Let the length of a rectangle is l and breadth is b.

Given, the difference between length and breadth is 25m.

⇒ l - b = 25 m ...(1)

Also, the perimeter of this rectangle is 210m.

⇒ 2(l + b) = 210

⇒ l + b = 105 ...(2)

solving equations (1) and (2) we get,

l = (25 + 105)/2 = 65 and b = (105 - 25)/2 = 40.

We have,

Length , l = 65 m

Breadth , b = 40 m

∴ The area of the rectangle = length × breadth

= l × b = 65 × 40 = 2600 m²

Therefore the area of the rectangle is 2600 m².