Math, asked by ranjitsiddharth, 1 day ago

The difference between the length and breadth of a rectangle is 15m. If the perimeter is 150m, then find the area of the rectangle.

Answers

Answered by umacademy24x7
2

Answer:

Step-by-step explanation:

Given that -

length( L) - Breadth ( B)  = 15 m

OR

L - B = 15                                 (1)

Perimeter = 150 m

perimeter of rectangle = 2 ( L + B )

OR

2 ( L + B ) = 150

L + B = 75                               (2)

Adding equation 1 and 2 then we get,

L - B = 15  

L + B = 75

-----------------

2L = 90

L = 90/2

L = 45 cm

Putting the value of L in equation 1 then

45 - B = 15

45 - 15 = B

30 = B

OR

B = 30 cm

hence,

length ( L) = 45 cm

breadth (B) = 30 cm

Answered by anvimalik867
1

Concept:-

It could look like a word or a number portrayal of the amount's math esteem. It could resemble a word or a number that represents the numerical value of the quantity. It could have the appearance of a word or a number that denotes the quantity's numerical value.

Given:-

We have been given that "The difference between the length and breadth of a rectangle is 15 m. If the perimeter is 150 m"

Find:-

We need to find the area of the rectangle.

Solution:-

Given that -

length( L)-Breadth ( B)= 15 m

OR

L - B = 15                                 (1)

Perimeter= 150 m

Perimeter of rectangle= 2 ( L + B )

OR

2 ( L + B ) = 150\\L + B = 75(2)

Adding equation 1 and 2 then we get,

L - B = 15  

L + B = 75

-----------------

2L = 90\\L = 90/2\\L = 45

Putting the value of L in equation 1 then

45 - B = 15\\45 - 15 = B\\30 = B

OR

B = 30 cm

So,

length ( L) = 45 cm

breadth (B) = 30 cm

\therefore Area=Length \times Breadth\\=45 \times 30\\=1350

Hence, the area of the rectangle.  is 1350 m^2.

#SPJ2

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