The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
Answers
Answered by
4
According to the question,
l-b=23m
then,l=b+23m
perimeter of rectangle=2(l+b)
206=2(b+23+b)
206/2=2b+23
103=2b+23
2b=103-23
2b=80
b=40
therefore, breadth=40m
l=b+23=40+23=63m
l-b=23m
then,l=b+23m
perimeter of rectangle=2(l+b)
206=2(b+23+b)
206/2=2b+23
103=2b+23
2b=103-23
2b=80
b=40
therefore, breadth=40m
l=b+23=40+23=63m
Answered by
11
Answer:
The area is 2520 m²
Step-by-step explanation:
Solution:
Length and breadth differ by = 23 m
Perimeter = 206 m
Area = ??
Let the -
- Breadth be b
- Length be (b + 23)
★ Perimeter =
⇒ 2(Length + Breadth)
⇒ 2(b + 23 + b) = 206
⇒ 2b + 23 = 103
⇒ 2b = 80
⇒ b = 80/2
⇒ b = 40
Breadth = 40
★ Length =
⇒ 40 + 33
⇒ 63
Length = 63
★ Area =
⇒ Length × Breadth
⇒ 63 × 40
⇒ 2520
Therefore, the area is 2520 m²
Similar questions