the difference between the measures of two acute angles of a right angled triangle is 72 find the measures of the angles in radian
Answers
Given :-
- Difference between the measures of two acute angles of a right angled triangle is 72°.
To Find :-
- find the measures of the angles in radian ..
Solution :-
Since It a right angle ∆, That Means one Angle is 90°.
So,
→ Sum of Rest two angles = 180° - 90° = 90°.
Now, Let us assume That, Rest two acute angles are a & b. where a > b.
Than,
→ a + b = 90° ---------------- Equation (1)
→ a - b = 72° (Given) ------------- Equation (2)
Adding Both Equations we get,
→ a + b + a - b = 90 + 72
→ 2a = 162°
→ a = 81° .
Putting in Equation (1) now,
→ 81 + b = 90
→ b = 90 - 81
→ b = 9°.
Hence, Rest Two acute angles are 9° and 81°..
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Now, we have to convert These angles into Radian.
we know that :-
☛ 180° = π radian
So,
➼ 180° = π radian
➼ 1 ° = (π/180) radian
➼ 9° = (π/180) * 9 = (π/20) rad.. (Ans).
Similarly,
➻ 81° = (π/180) * 81 = (9π/20) rad (Ans).
Hence, Measures of the Rest two acute angles in radian is (π/20)rad. & (9π/20)rad. .
The difference between the measures of two acute angles of a right angled triangle is 72 find the measures of the angles in radian
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We know right angle = 90°
Sum of two angles would be = 180° - 90° = 90°
So, let the other two acute angle be x & y, where x >y
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=> a + b = 90° ___________equ(1)
=> a - b = 72° ___________equ(2)
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By adding both equations,we get-
=> a + b + a - b = (90 + 72)°
=> 2a = 162°
=> A= 81°
Putting equ(1) ,
=> 81° + b = 90°
=> B = (90- 81)°
=> B = 9°
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Hence,the other two acute angles are 81° and 9°
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Now,we have to convert them into radians,
We know that 180° = π radian
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converting 9° angle to radian
=> 180° = π radian
=> 1° = ( π/180) radian
=> 9° = (π/180)×9 raidan
=>(π/20) radian
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converting 81° angle to radian
=> 180° = π radian
=> 1° = (π/180)
=> 81° = (π/180)×81 radian
=> (9π/20) radian