Math, asked by raj9797337843, 2 months ago

The difference between the place
value of 9 in the greatest and smallest
4-digit numbers formed by using the
digits 4,6,0 and 9 is
a) 5992
b) 8991
c) 8199
d) 7991​

Answers

Answered by tihorsinha129
1

Answer:

b. 8991

Step-by-step explanation:

Place Value of digit 8 in Greatest Four digit no =9000

Place value of digit 8 in smallest four digit no =9

Therefore, required difference =9000−9=8991

Answered by wanrimekathabah
1

Answer:

b) 8991

Step-by-step explanation:

Greatest 4-digit number = 9640

Smallest 4-digit number = 4069

Place value of 9 in 9640 is 9000

Place value of 9 in 4069 is 9

Therefore, the difference between the place value of 9 in the greatest and smallest 4 -digit number is 9000 - 9 = 8991

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