The difference between the semi perimeter and sides of a triangle are 10cm, 6cm&,4cm respectively. Find the area of the triangle
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Answer:
Step-by-step
let the sides of a triangle be a,b and c
According to the condition,
s-a=10→1
s-b=6→2
s-c=4→3
Adding 1,2 and 3
[s-a]+[s-b]+[s-c]=10+6+4
3s-[a+b+c]=20
3s-2s=20 {a+b+c/2=2s}
s=20→4
area of the triangle = √s[s-a][s-b][s-c]
√20×10×6×4
On solving,
40√3cm² is the area of triangle
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