the difference between the semi perimeter and the sides of a triangle are 3cm 17th 34ch respectively the area of the triangle is
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Answer:
Given s−a=8cm⋯(1)
s−b=7cm⋯(2)
s−c=5cm⋯(3)
Where a, b, c are sides of triangle
s
2
is 1 semi perimeter ie s=
2
a+b+c
(1) + (2) + (3)
⇒3s−(a+b+c)=20cm
⇒3s−(25)=20cm
⇒s=20cm
Area of triangle =
s(s−a)(s−b)(s−c)
=
20(8×7×5)
=
5600
=20
14
=59cm
solution
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