the difference between the semi perimeter and the sides of a triangle ABC are 8cm, 7cm and 5cm respectively . Find the area of triangle is
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THE DIFFERENCE BETWEEN THE SEMI PERIMETER ___.....
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The difference between the semi-perimeter and the sides of triangle ABC are 8 cm, 7 cm and 5 cm, respectively. Find its semi-perimeter.
NOW___=>>>>SOLUTION<<<<<<<<
Let the semi-perimeter of the triangle be s. Let the sides of the triangle be a, b and c. Given: s – a = 8, s – b = 7 and s – c = 5Adding all the above equations, we get (s – a) + (s – b) + (s – c) = 8 + 7 + 5 ⇒ 3s – (a + b + c) = 20 ⇒ 3s – 2s = 20 [Since s = (a+b+c)/2] ⇒ s = 20 cm Thus the semi-perimeter is 20 cm
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THE DIFFERENCE BETWEEN THE SEMI PERIMETER ___.....
=>>
The difference between the semi-perimeter and the sides of triangle ABC are 8 cm, 7 cm and 5 cm, respectively. Find its semi-perimeter.
NOW___=>>>>SOLUTION<<<<<<<<
Let the semi-perimeter of the triangle be s. Let the sides of the triangle be a, b and c. Given: s – a = 8, s – b = 7 and s – c = 5Adding all the above equations, we get (s – a) + (s – b) + (s – c) = 8 + 7 + 5 ⇒ 3s – (a + b + c) = 20 ⇒ 3s – 2s = 20 [Since s = (a+b+c)/2] ⇒ s = 20 cm Thus the semi-perimeter is 20 cm
...I HOPE U UNDERSTAND MY ANSWER FRIEND___:-)
SO MARK ME AS THE BRAINLIST___:-)
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Step-by-step explanation:
Let the semi-perimeter of the triangle be s.
Let the sides of the triangle be a, b and c.
Given: s – a = 8, s – b = 7 and s – c = 5 Adding all the above equations, we get (s – a) + (s – b) + (s – c) = 8 + 7 + 5
⇒ 3s – (a + b + c) = 20
⇒ 3s – 2s = 20 [Since s = (a+b+c)/2]
⇒ s = 20 cm
Thus the semi-perimeter is 20 cm
now by using herons formula we can find the area
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