Question

The difference between the semiperimeter and the sides of a A ABC are
8 cm, 7 cm and 5 cm respectively. Find the area of the triangle.​

Answer 1

Answer:

let semi-perimeter is s

again let the side is triangle are a,b and c

given that

(s - a)=8

(s - c)=7

(s- c)=5

after adding these,

we get,

3s-2s= 20

we know that,

s= (a+b+c)/2

2s=(a+b+c)

so ,

3s- 2s= 20

s= 20

Now,

Area = √s(s-a)(s-b)(s-c)

= √( 20)(8)(7)(5)

= 20√14 cm^2

Answer 2

Answer:

given,

the difference between semi perimeter (s) and sides of a triangle are 8,7, and 5

which means

(s-a) =8

(s-b) = 7

(s-c) = 5

where a,b,c are the length of the sides of the triangle ABC

area of triangle formula

____________

√s(s−a)(s−b)(s−c)

________

= √s(8)(7)(5)

_____

= √s(280)