The difference between the semiperimeter and the sides of a tiangle ABC are
8 cm, 7 cm and 5 cm respectively. Find the area of the triangle
Answers
HLO FRIEND______:-)
THE DIFFERENCE BETWEEN THE SEMI PERIMETER ___.....
=>>
The difference between the semi-perimeter and the sides of triangle ABC are 8 cm, 7 cm and 5 cm, respectively. Find its semi-perimeter.
NOW___=>>>>SOLUTION<<<<<<<<
Let the semi-perimeter of the triangle be s. Let the sides of the triangle be a, b and c. Given: s – a = 8, s – b = 7 and s – c = 5Adding all the above equations, we get (s – a) + (s – b) + (s – c) = 8 + 7 + 5 ⇒ 3s – (a + b + c) = 20 ⇒ 3s – 2s = 20 [Since s = (a+b+c)/2] ⇒ s = 20 cm Thus the semi-perimeter is 20 cm
...I HOPE U UNDERSTAND MY ANSWER FRIEND___:-)
SO MARK ME AS THE BRAINLIST___:-)
Answer:
20√14 cm
Step-by-step explanation:
s-a=8cm ...........1
s-b=7cm ............2
s-c=5cm ............3
semiperimeter s=a+b+c/2
from above , add 1,2,3
3s-(a+b+c)=20
3s-(2s)=20
s=20cm
area of triangle =√s(s-a)(s-b)(s-c)
=√20*8*7*5
=√5600
=20√14cm
mark as brainliest answer and follow me