Math, asked by rohitthomasjacob, 6 months ago

The difference between the Si and CI for 20000 rupees for 2 years at the rate of 5% Per annum

Answers

Answered by nayanazara12
9

Step-by-step explanation:

ANSWER

P=Rs.20,000

n=2

Let the rate be r

then 

SI=100P×r×t

SI=10020000×r×2

CI=P[(1+100r)n−1]

CI=20000[(1+100r)2−1]

⟹CI−SI=200

⟹20000[(1+100r)2−1−1002r]=200

⟹20000[10000r2]=200⟹r=10

Answered by supriyagoswami242001
2

P=Rs.20,000

n=2

Let the rate be r

then

SI=

100

P×r×t

SI=

100

20000×r×2

CI=P[(1+

100

r

)

n

−1]

CI=20000[(1+

100

r

)

2

−1]

⟹CI−SI=200

⟹20000[(1+

100

r

)

2

−1−

100

2r

]=200

⟹20000[

10000

r

2

]=200

⟹r=10

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