The difference between the sides containing a right angle in a right angled triangle is 14 cm . The area of a triangle is 120 cm.calculate the perimeter of the triangle
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Suppose one side of a right angle triangle is x
then another side is x+14
Area of a triangle is 120
1/2 * Alti * Base =120
1/2 * x * x+14 = 120
x^2+ 14x = 120*2
x^2+ 14x = 240
x^2+ 14x-240 =0
x^2+16x-15x-240=0
x(x+16)-15 (x+16)=0
(x-15) (x+16) =0
x-15=0 OR x-16=0
x=15 OR x=16
then another side is x+14
Area of a triangle is 120
1/2 * Alti * Base =120
1/2 * x * x+14 = 120
x^2+ 14x = 120*2
x^2+ 14x = 240
x^2+ 14x-240 =0
x^2+16x-15x-240=0
x(x+16)-15 (x+16)=0
(x-15) (x+16) =0
x-15=0 OR x-16=0
x=15 OR x=16
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