The difference between the square of two consecutive number is 15 .Find the number.
Answers
Answered by
30
Hey friend, Harish Here.
Here is your answer:
Let the consecutive numbers be (n), (n+1)
We know that a² - b² = (a+b)(a-b)
Then (n+1)² - n² = (n+1+n) (n+1-n) -- ( By applying the above identity)
=> 15 = (2n+1) (1)
=> 15 = 2n+1
=> 14= 2n
∴ n = 7. & n+1 =8
So, the two consecutive numbers are 7 & 8.
Hope my answer is helpful to u.
Here is your answer:
Let the consecutive numbers be (n), (n+1)
We know that a² - b² = (a+b)(a-b)
Then (n+1)² - n² = (n+1+n) (n+1-n) -- ( By applying the above identity)
=> 15 = (2n+1) (1)
=> 15 = 2n+1
=> 14= 2n
∴ n = 7. & n+1 =8
So, the two consecutive numbers are 7 & 8.
Hope my answer is helpful to u.
Answered by
6
let the numbers be x& x-1
therefore, according to the condition,
(x)^2-(x-1)^2=15
x^2-x^2-1+2x=15
2x-1=15
2x=15+1=16
x=16/2=8
x=8
x+1=8+1=9
hence the number is x (x+1)
answer=89
please mark my answer as brainliest.
hope it helps.............please feel free to ask doubts to me
therefore, according to the condition,
(x)^2-(x-1)^2=15
x^2-x^2-1+2x=15
2x-1=15
2x=15+1=16
x=16/2=8
x=8
x+1=8+1=9
hence the number is x (x+1)
answer=89
please mark my answer as brainliest.
hope it helps.............please feel free to ask doubts to me
dhonisuresh0703:
how bro im taking minus inside directly
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