Question

the difference between the square of two consecutive numbers is 31 . Find the numbers​

Answer 1

Step-by-step explanation:

Let the two consecutive square be x^2 and (x+1)^2

A/Q,

x^2-(x+1)^2=31

x^2-(x^2+2.x.1+ 1^2)=31

x^2-x^2+2x+1=31

2x=31-1

x=30/2

x=15

Therefore,the two consecutive numbers are 225 and256

Answer 2

Step-by-step explanation:

consider that numbers=n,n+1

(n+1)^2-n^2=31

(n^2+2n+1)-n^2=31

2n+1=31

2n=30

n= 15

hence that numbers are, 15 and 16.