the difference between the squares of 2 consecutive numbers is 95. then the numbers are
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The numbers are 47 and 48.
Answered by
1
let the first consecutive no be x
let the second consecutive no be x+1
(x+1)² -x² =95
x²+1+2x-x²=95
2x=95-1=94
x=94/2=47
hence numbers are
47,48
let the second consecutive no be x+1
(x+1)² -x² =95
x²+1+2x-x²=95
2x=95-1=94
x=94/2=47
hence numbers are
47,48
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