the difference between the squares of two consecutive numbers is 141 . find the numbers.
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Answer:
a2-b2=141 now u can solve it further
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let the consecutive number be x
x²- (x+1)² = 141
x² -( x²+ 1+ 2x) = 141
x² - x² - 1 - 2x = 141
-2x = 141+1
-2x = 142
x = 142/2 = 71
★hope it helps you!!!
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