Question

The difference between the squares of two consecutive numbers is 31.find the numbers

Answer 1

Let the first number is any variable, taking x

So other number will be ( x + 1 ) ,




Given that the difference of the squares of ( x + 1 ) and x is 31


= > ( x )^2 - ( x + 1 )^2 = 31

= > x^2 - x^2 + 1 + 2x = 31

= > 1 + 2x = 31

= > 2x = 31 - 1

= > x = 30 / 2

= > x = 15




Hence, required consecutive numbers are :-


First number = x = 15

Second number = ( x + 1 ) = ( 15 + 1 ) = 16

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Answer 2

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