Question

the difference between the squares of two consecutive integers is 47 find the numbers

Answer 1

Let the two consecutive numbers be n, &(n+1), then ;
(n+1)^2 - n^2 = 47
n^2 + 1 + 2n - n^2 = 47
2n+1 = 47
n = 23

Therefore the required numbers are 23 and 24.

hope this helped you ........!

Answer 2

let the two consecutive integers be x and (x+1)
according to question..
(x+1)^2 -x^2=47
x^2 +1 +2x -x^2= 47
2x+1 =47
2x= 47-1
2x=46
x= 46/2 =23
so consecutive no. are 23 and 24...ans...