the difference between the squares of two consecutive nos. is 47.find the numbers and the method
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Let one of the numbers be x, then next number which is consecutive with the first will be ' x + 1 '.
as given , (x + 1)^2 - x^2 = 47.
x^2 + 1 + 2x - x^2 = 47
2x = 47 - 1.
x = 46/2 = 23.
so, the numbers are 23,24.
as given , (x + 1)^2 - x^2 = 47.
x^2 + 1 + 2x - x^2 = 47
2x = 47 - 1.
x = 46/2 = 23.
so, the numbers are 23,24.
Answered by
1
Answer:
Hola...
Step-by-step explanation:
Let the consecutive intergers be x and x + 1
( x + 1 )² - x ² = 47
x² + 2x + 1 - x² = 47
2x = 47 - 1
x = 46 ÷ 2
x = 23
x+1 = 23 + 1 = 24
Therefore, The two numbers are 23 and 24
Hope It Helps You!!!
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