the difference between the squares of two consecutive number is 31 find the numbers
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Let the two numbers be x and x + 1.
Given the difference between the squares of two consecutive number is 31.
(x + 1)^2 - x^2 = 31
x^2 + 1 + 2x - x^2 = 31
2x + 1 = 31
2x = 30
x = 15.
The other number will be x + 1 = 15 + 1 = 16.
The numbers are 15 and 16.
Hope this helps!
Given the difference between the squares of two consecutive number is 31.
(x + 1)^2 - x^2 = 31
x^2 + 1 + 2x - x^2 = 31
2x + 1 = 31
2x = 30
x = 15.
The other number will be x + 1 = 15 + 1 = 16.
The numbers are 15 and 16.
Hope this helps!
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