Question

The difference between the squares of two positive numbers is 576, and one
number is exactly 60% of the other number. Find the larger of the two positive
numbers.​

Answer 1

Answer:

First positive number is greater than the other positive number.

Step-by-step explanation:

Let the first positive number be x.

Then,(x)^2 -(60% of x)^2 =576

=>x^2 -(60/100 × x)^2 =576

=>x^2 -(3/5 x)^2 =576

=>x^2 -9/25 x^2 =576

=>25x^2 -9x^2 /25 =576

=>16x^2 /25 =576

=>x^2 =576×25 /16

=>x^2 =900

=>x=√900

=>x=30.

Hence, first positive number=30

and the other positive number=60% of 30

=60/100 ×30

=18.

Therefore, first positive number is greater than the other positive number by 12.