The difference between the total number of hydrogen atoms in 78 g of ethyne and 168 g of baking soda is
Answers
Answer: 4*NA atoms of hydrogen or 24.088 * 10²³ atoms of hydrogen
Explanation:
Required formula:
No. of atoms = [Mass/Molecular weight] * [Avogadro’s constant] * [No. of atoms in a molecule]
Where Avogadro’s constant, NA = 6.022 * 10²³ mol⁻¹
Step 1: finding hydrogen atoms in 78 gms of ethyne
The molecular weight of ethyne, C₂H₂ = 26 g/mol
So, 26 g/mol of C₂H₂contains (2*NA) atoms of hydrogen
∴ The total no. of Hydrogen atoms in 78 g Ethyne = [2*NA/26] * 78 = 6 * NA ….. (i)
Step 2 : finding hydrogen atoms in 168 gms of baking soda
The molecular weight of baking soda, NaHCO₃ = 84 g/mol
So, 84 g/mol of NaHCO₃ contains (1*NA) atoms of hydrogen
∴ The total no. of Hydrogen atoms in 168 g NaHCO₃ = [1*NA/84] * 168 = 2 * NA ….. (ii)
Step 3: Difference between the total number of hydrogen atoms in 78 g of Ethyne & 168 g of Baking soda
Therefore, from (i) & (ii), we get
The difference between the total no .of hydrogen atoms as,
= [6 * NA] – [2 * NA]
= 4 * NA
= 4 * 6.022 * 10²³ ……. [since NA = 6.022 * 10^23 mol⁻¹]
= 24.088 * 10²³
Answer:
Ethane C2H2
= 12*2 + 2*1 =26g
So
78g Ethane will contian= 2/26 *78
= 6 Hydrogen
And
NaHCO2 = 23*1 + 12*1 + 16*2
= 84
So
168g Soda will contain = 1/84 *168
=2 Hydrogen
In Ethane 4 Hydrogen atom are more then Baking Soda.