The difference between the total number of hydrogen atoms in 78 g of ethyne and 168 g of baking soda is
Answers
Dear Student,
◆ Answer -
Difference = 2.409×10^24 atoms
● Explanation -
Moles of ethyne are calculated as -
n(ethyne) = 78 / 26
n(ethyne) = 3 mol
Each mol of ethyne contains 6.022×10^23 molecules of ethyne and each molecule will have 2 H-atoms.
So total H-atoms in ethyne is -
H-atoms in ethyne = 3 × 6.022×10^23 × 2
H-atoms in ethyne = 3.613×10^24 atoms
Moles of baking soda are calculated as -
n(baking soda) = 168 / 84
n(baking soda) = 2 mol
Each mol of baking soda contains 6.022×10^23 molecules of baking soda and each molecule will have 1 H-atom.
So total H-atoms in baking soda is -
H-atoms in baking soda = 2 × 6.022×10^23 × 1
H-atoms in baking soda = 1.204×10^24 atoms
Therefore, difference between H-atoms of ethyne and baking soda is -
Difference =
H-atoms in ethyne - H-atoms in baking soda
Difference = 3.613×10^24 - 1.204×10^24
Difference = 2.409×10^24 atoms
Thanks dear. Hope this helps you...