Question

The difference between the total number of hydrogen atoms in 78 g of ethyne and 168 g of baking soda is.

Answer 1

Answer: The difference between the number of hydrogen atoms in ethyne and baking soda is $2.4088\times 10^{24}$

Explanation:

According to mole concept:

1 mole of a gas contains $6.022\times 10^{23}$ number of molecules.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$     .......(1)

• For ethyne $(C_2H_2)$

Given mass of ethyne = 78 g

Molar mass of ethyne = 26 g/mol

Putting values in equation 1, we get:

$\text{Moles of ethyne}=\frac{78g}{26g/mol}=3mol$

1 mole of ethyne contains 2 mole of carbon atom and 2 mole of hydrogen atom

So, 3 moles of ethyne gas will contain $(3\times 2\times 6.022\times 10^{23}=3.6132\times 10^{24})$ number of hydrogen atoms

Number of hydrogen atoms in given amount of ethyne = $3.6132\times 10^{24})$

• For baking soda $(NaHCO_3)$

Given mass of baking soda = 168 g

Molar mass of baking soda = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of baking soda}=\frac{168g}{84g/mol}=2mol$

1 mole of baking soda contains 1 mole of sodium atom, 1 mole of carbon atom, 1 mole of hydrogen atom and 3 moles of oxygen atoms

So, 2 moles of baking soda will contain $(2\times 1\times 6.022\times 10^{23}=1.2044\times 10^{24})$ number of hydrogen atoms

Number of hydrogen atoms in given amount of baking soda = $1.2044\times 10^{24})$

Difference in the number of hydrogen atoms = $(3.6132-1.2044)\times 10^{24}=2.4088\times 10^{24}$

Hence, the difference between the number of hydrogen atoms in ethyne and baking soda is $2.4088\times 10^{24}$