Question

the difference between the two age of two cousins is 10 years. 15 years ago if the elder one was twice as older as the younger one find their present age​

Answer 1

Answer:

elder cousin = x = 35 years

younger cousin = y = 25 years

Step-by-step explanation:

let the age of elder cousin be x

let the age of younger cousin be y

difference between there ages is 10

x - y = 10 equ (1)

age of x 15 years ago x - 15

age of y 15 years ago y - 15

x was twice the age of y 15 years ago

x - 15 = 2(y - 15)

x - 15 = 2y - 30

x - 2y = - 30 + 15

x - 2y = -15 equ (2)

subtracting equ (1) and (2)

we get

y = 25

substitute y = 25 in equ (1)

x - y = 10

x - 25 = 10

x = 10 + 25

x = 35

elder cousin = x = 35 years

younger cousin = y = 25 years

hope you get your answer